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Full Exam Name: Junos, Associate (JNCIA-Junos)
Vendor Name: Juniper
Exam Code: JN0-105
Questions with Answers (PDF) 65
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NEW QUESTION: 1
NG-SDH equipment can be used for complex networking. Which of the following statements about protection or service configuration are true?
A. On a network where MSP rings and SNCP rings share fiber resources, all timeslots can be configured for SNCP services, because SNCP service configuration is flexible and SNCP services does not require special overheads to transmit protocol information.
B. OSN equipment does not support logical systems. You do not need to specify master and slave nodes during DNI service configuration.
C. Two SNCP rings are tangent. The source and sink work in dual transmission and selective receiving mode. The line boards corresponding to the tangent node are configured with bidirectional pass-through services. Given the preceding configurations, services can be protected after a fiber cut.
D. Two MSP rings are intersected. To prevent service interruption upon failure of one intersecting node, you need to configure an SNCP service pair on an intersecting node to support dual transmission and selective receiving.
Answer: B,D

NEW QUESTION: 2
If a dealer has interest on one side, and the other side is dealt away, the broker should:
A. Immediately put the price "under reference" and check with the dealer to ascertain his original intention.
B. None of the above.
C. Continue with the order.
D. Cancel the order.
Answer: A

NEW QUESTION: 3
JN0-105 Kostenlos Downloden
JN0-105 Kostenlos Downloden
Answer:
Explanation:
First we need to find out 5 parameters
(Bandwidth, Delay, Reliability, Load, MTU)
of the s0/0/0 interface
(the interface of R2 connected to R4) for redistribution:
R2#show interface s0/0/0
Write down these 5 parameters, notice that we have to divide the Delay by 10 because the metric unit is in tens of microsecond. For example, we get Bandwidth=1544 Kbit, Delay=20000 us, Reliability=255, Load=1, MTU=1500 bytes then we would redistribute as follows:
R2#config terminal
R2(config)# router ospf 1
R2(config-router)# redistribute eigrp 100 metric-type 1 subnets
R2(config-router)#exit
R2(config-router)#router eigrp 100
R2(config-router)#redistribute ospf 1 metric 1544 2000 255 1 1500
Note: In fact, these parameters are just used for reference and we can use other parameters with no problem.
If the delay is 20000us then we need to divide it by 10, that is 20000 / 10 = 2000) For R3 we use the show interface fa0/0 to get 5 parameters too R3#show interface fa0/0 For example we get Bandwidth=10000 Kbit, Delay=1000 us, Reliability=255, Load=1, MTU=1500 bytes R3#config terminal R3(config)#router ospf 1 R3(config-router)#redistribute eigrp 100 metric-type 1 subnets R3(config)#exit R3(config-router)#router eigrp 100 R3(config-router)#redistribute ospf 1 metric 10000 100 255 1 1500 Finally you should try to "show ip route" to see the 172.16.100.1 network (the network behind R4) in the routing table of R1 and make a ping from R1 to this network.
Note: If the link between R2 and R3 is FastEthernet link, we must put the command below under EIGRP process to make traffic from R1 to go through R3 (R1 -> R2 -> R3 -> R4), which is better than R1 -> R2 -> R4.
R2(config-router)# distance eigrp 90 105
This command sets the Administrative Distance of all EIGRP internal routes to 90 and all EIGRP external routes to 105, which is smaller than the Administrative Distance of OSPF (110) -> the link between R2 & R3 will be preferred to the serial link between R2 & R4.
Note: The actual OPSF and EIGRP process numbers may change in the actual exam so be sure to use the actual correct values, but the overall solution is the same.

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