C_TS422_2023-German Exam Questions

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Full Exam Name: SAP S/4HANA Cloud Private Edition - Production Planning and Manufacturing (C_TS422_2023 Deutsch Version)
Vendor Name: SAP
Exam Code: C_TS422_2023-German
Questions with Answers (PDF) 65
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NEW QUESTION: 1
C_TS422_2023-German Trainingsunterlagen
RMAN> BACKUP VALIDATE DATABASE;
RMAN> RECOVER CORRUPTION LIST;
C_TS422_2023-German Trainingsunterlagen
A. Option A
B. Option C
C. Option D
D. Option B
Answer: C
Explanation:
Explanation
Reference
http://www.dba-oracle.com/t_rman_36_validate_backup.htm

NEW QUESTION: 2
Microsoft 365サブスクリプションがあります。監査が有効になっています。
User1という名前のユーザーは、Group1という名前の動的セキュリティグループのメンバーです。
User1がGroup1のメンバーではなくなっていることがわかります。
監査ログを検索して、User1がGroup1から削除された理由を特定する必要があります。
検索で使用する2つのアクションはどれですか?回答するには、回答エリアで適切なアクティビティを選択します。
注:それぞれの正しい選択には1ポイントの価値があります。
C_TS422_2023-German Trainingsunterlagen
Answer:
Explanation:
C_TS422_2023-German Trainingsunterlagen
Explanation
C_TS422_2023-German Trainingsunterlagen
C_TS422_2023-German Trainingsunterlagen
References:
https://docs.microsoft.com/en-us/office365/securitycompliance/search-the-audit-log-in-security-and-compliance

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:
C_TS422_2023-German Trainingsunterlagen
You need to determine the total number of customers who have either deposit accounts or loan accounts, but not both types of accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
E. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
F. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo
G. CustNo IS NULL
H. CustNo
I. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
J. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
K. CustNo = L.CustNo
Answer: I
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

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